510mA per hour is nonsensical because A is an instantaneous measurement. 510 mAh/h is 510 mA. I guess you need a backpack to carry the battery around if you want the watch to last all day.
The battery has the storage capacity to pass 510 mA in an hour. If you discharge at half the capacity of 255 mAh (0.5C) it will be empty after 2 hours.
If it was to draw 51 mAh (0.1C) it would last 10 hours.
But if it would draw 1020 mAh (2C) it would only last 30 minutes
Not really, it makes sense to give a max current. If a car’s top speed is listed as 200 km per hour, it does not mean that it goes this fast continuously.
Really? I have a camera that is rated “3.7 V, 2 A” but only draws that amount from the battery when the flash capacitor is recharging. Yes, the normal current draw would be more helpful, and in case of a watch, the standby current.
This may be the charging current but it would be pretty unusual to pick a value slightly above what legacy USB can deliver (500 mA).
The max rating is important so your powersupply/battery can be sized accordingly. No powersupply can provide a abitrary current at their rated voltage.
So this is 510 mA per hour, I guess. That or it just draws 510 mA continuously
510mA per hour is nonsensical because A is an instantaneous measurement. 510 mAh/h is 510 mA. I guess you need a backpack to carry the battery around if you want the watch to last all day.
The battery has the storage capacity to pass 510 mA in an hour. If you discharge at half the capacity of 255 mAh (0.5C) it will be empty after 2 hours.
If it was to draw 51 mAh (0.1C) it would last 10 hours.
But if it would draw 1020 mAh (2C) it would only last 30 minutes
This is the winning response I think.
Not really, it makes sense to give a max current. If a car’s top speed is listed as 200 km per hour, it does not mean that it goes this fast continuously.
I get this is a battery but the units don’t make sense unless it’s going at 100% all the time
Really? I have a camera that is rated “3.7 V, 2 A” but only draws that amount from the battery when the flash capacitor is recharging. Yes, the normal current draw would be more helpful, and in case of a watch, the standby current.
This may be the charging current but it would be pretty unusual to pick a value slightly above what legacy USB can deliver (500 mA).
The max rating is important so your powersupply/battery can be sized accordingly. No powersupply can provide a abitrary current at their rated voltage.